This program multiplies a 3x3 matrix by another 3x3 matrix. Each number in the result matrix is found by multiplying one row from the first matrix with one column from the second matrix.
#includeint main() { int a[3][3] = { {1, 2, 3}, {4, 5, 6}, {7, 8, 9} }; int b[3][3] = { {9, 8, 7}, {6, 5, 4}, {3, 2, 1} }; int result[3][3]; int i, j, k; for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { result[i][j] = 0; } } for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { for (k = 0; k < 3; k++) { result[i][j] += a[i][k] * b[k][j]; } } } for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { printf("%d ", result[i][j]); } printf("\n"); } return 0; }